The compounds (X) and (Y) are formed by repla | vedclass

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(B) The starting molecule is $2$-bromobutane. The carbon atom bearing $H_a$ and $H_b$ is a prochiral center. Replacing $H_a$ with $D$ creates a chiral

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Diastereomers

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(B) The starting molecule is $2$-bromobutane. The carbon atom bearing $H_a$ and $H_b$ is a prochiral center. Replacing $H_a$ with $D$ creates a chiral center at that carbon,resulting in one stereoisomer $(X)$. Replacing $H_b$ with $D$ creates the other stereoisomer $(Y)$ at the same carbon. Since the rest of the molecule (the chiral center at the $C-2$ position) remains unchanged,the two resulting molecules $(X)$ and $(Y)$ are diastereomers because they have different configurations at one chiral center while having the same configuration at the other.

The compounds $(X)$ and $(Y)$ are formed by replacing $H_a$ with $D$ (while keeping $H_b$ as $H$) and replacing $H_b$ with $D$ (while keeping $H_a$ as $H$) respectively in the given molecule. What is the relationship between $(X)$ and $(Y)$?

Similar Questions

Calculate the total number of stereoisomers for the given compound.

Which of the given statement(s) about $N$, $O$, $P$ and $Q$ with respect to $M$ is (are) correct?
$(A)$ $M$ and $N$ are non-mirror image stereoisomers
$(B)$ $M$ and $O$ are identical
$(C)$ $M$ and $P$ are enantiomers
$(D)$ $M$ and $Q$ are identical

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